For example print all line that do not contain the word bar: You can use -v option to print inverts the match that is, it matches only those lines that do not contain the given word. Sample outputs: 1:root:x:0:0:root:/root:/bin/bashġ042:rootdoor:x:0:0:rootdoor:/home/rootdoor:/bin/cshģ319:initrootapp:x:0:0:initrootapp:/home/initroot:/bin/ksh Pass the -n option to precede each line of output with the number of the line in the text file from which it was obtained: The grep can report the number of times that the pattern has been matched for each file using -c (count) option: $ egrep -w 'word1|word2' /path/to/file How can I count line when words has been matched $ grep -w 'boo' file How to use grep to search 2 different words You can force the grep command to select only those lines containing matches that form whole words i.e.

When you search for boo, grep will match fooboo, boo123, barfoo35 and more. The inclusion of the file names in the output data can be suppressed by using the -h option as follows:Īddresses1=192.168.1.5 24 192.168.1.2 How to use grep to search words only You will see result for 192.168.1.5 on a separate line preceded by the name of the file (such as /etc/ppp/options) in which it was found. read all files under each directory for a string “192.168.1.5”

$ grep -i 'boo' /etc/passwd How to use grep recursively You can force grep to ignore word case i.e match boo, Boo, BOO and all other combination with the -i option: Search /etc/passwd file for boo user, enter: Cat otherfile | grep 'something' command | grep 'something' command option1 | grep 'data' grep -color 'data' fileName

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